Optimal. Leaf size=643 \[ \frac{a^{3/4} \left (\sqrt{a}+\sqrt{b} \tan ^2(x)\right ) \sqrt{\frac{a+b \tan ^4(x)}{\left (\sqrt{a}+\sqrt{b} \tan ^2(x)\right )^2}} \text{EllipticF}\left (2 \tan ^{-1}\left (\frac{\sqrt [4]{b} \tan (x)}{\sqrt [4]{a}}\right ),\frac{1}{2}\right )}{3 \sqrt [4]{b} \sqrt{a+b \tan ^4(x)}}+\frac{\sqrt [4]{b} (a+b) \left (\sqrt{a}+\sqrt{b} \tan ^2(x)\right ) \sqrt{\frac{a+b \tan ^4(x)}{\left (\sqrt{a}+\sqrt{b} \tan ^2(x)\right )^2}} \text{EllipticF}\left (2 \tan ^{-1}\left (\frac{\sqrt [4]{b} \tan (x)}{\sqrt [4]{a}}\right ),\frac{1}{2}\right )}{2 \sqrt [4]{a} \left (\sqrt{a}-\sqrt{b}\right ) \sqrt{a+b \tan ^4(x)}}-\frac{\sqrt [4]{b} \left (\sqrt{a}-\sqrt{b}\right ) \left (\sqrt{a}+\sqrt{b} \tan ^2(x)\right ) \sqrt{\frac{a+b \tan ^4(x)}{\left (\sqrt{a}+\sqrt{b} \tan ^2(x)\right )^2}} \text{EllipticF}\left (2 \tan ^{-1}\left (\frac{\sqrt [4]{b} \tan (x)}{\sqrt [4]{a}}\right ),\frac{1}{2}\right )}{2 \sqrt [4]{a} \sqrt{a+b \tan ^4(x)}}-\frac{1}{2} \sqrt{a+b} \tan ^{-1}\left (\frac{\sqrt{a+b} \tan (x)}{\sqrt{a+b \tan ^4(x)}}\right )+\frac{1}{3} \tan (x) \sqrt{a+b \tan ^4(x)}-\frac{\sqrt{b} \tan (x) \sqrt{a+b \tan ^4(x)}}{\sqrt{a}+\sqrt{b} \tan ^2(x)}+\frac{\sqrt [4]{a} \sqrt [4]{b} \left (\sqrt{a}+\sqrt{b} \tan ^2(x)\right ) \sqrt{\frac{a+b \tan ^4(x)}{\left (\sqrt{a}+\sqrt{b} \tan ^2(x)\right )^2}} E\left (2 \tan ^{-1}\left (\frac{\sqrt [4]{b} \tan (x)}{\sqrt [4]{a}}\right )|\frac{1}{2}\right )}{\sqrt{a+b \tan ^4(x)}}-\frac{\left (\sqrt{a}+\sqrt{b}\right ) (a+b) \left (\sqrt{a}+\sqrt{b} \tan ^2(x)\right ) \sqrt{\frac{a+b \tan ^4(x)}{\left (\sqrt{a}+\sqrt{b} \tan ^2(x)\right )^2}} \Pi \left (-\frac{\left (\sqrt{a}-\sqrt{b}\right )^2}{4 \sqrt{a} \sqrt{b}};2 \tan ^{-1}\left (\frac{\sqrt [4]{b} \tan (x)}{\sqrt [4]{a}}\right )|\frac{1}{2}\right )}{4 \sqrt [4]{a} \sqrt [4]{b} \left (\sqrt{a}-\sqrt{b}\right ) \sqrt{a+b \tan ^4(x)}} \]
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Rubi [A] time = 0.49573, antiderivative size = 643, normalized size of antiderivative = 1., number of steps used = 12, number of rules used = 9, integrand size = 17, \(\frac{\text{number of rules}}{\text{integrand size}}\) = 0.529, Rules used = {3670, 1336, 195, 220, 1209, 1198, 1196, 1217, 1707} \[ \frac{a^{3/4} \left (\sqrt{a}+\sqrt{b} \tan ^2(x)\right ) \sqrt{\frac{a+b \tan ^4(x)}{\left (\sqrt{a}+\sqrt{b} \tan ^2(x)\right )^2}} F\left (2 \tan ^{-1}\left (\frac{\sqrt [4]{b} \tan (x)}{\sqrt [4]{a}}\right )|\frac{1}{2}\right )}{3 \sqrt [4]{b} \sqrt{a+b \tan ^4(x)}}-\frac{1}{2} \sqrt{a+b} \tan ^{-1}\left (\frac{\sqrt{a+b} \tan (x)}{\sqrt{a+b \tan ^4(x)}}\right )+\frac{1}{3} \tan (x) \sqrt{a+b \tan ^4(x)}-\frac{\sqrt{b} \tan (x) \sqrt{a+b \tan ^4(x)}}{\sqrt{a}+\sqrt{b} \tan ^2(x)}+\frac{\sqrt [4]{b} (a+b) \left (\sqrt{a}+\sqrt{b} \tan ^2(x)\right ) \sqrt{\frac{a+b \tan ^4(x)}{\left (\sqrt{a}+\sqrt{b} \tan ^2(x)\right )^2}} F\left (2 \tan ^{-1}\left (\frac{\sqrt [4]{b} \tan (x)}{\sqrt [4]{a}}\right )|\frac{1}{2}\right )}{2 \sqrt [4]{a} \left (\sqrt{a}-\sqrt{b}\right ) \sqrt{a+b \tan ^4(x)}}-\frac{\sqrt [4]{b} \left (\sqrt{a}-\sqrt{b}\right ) \left (\sqrt{a}+\sqrt{b} \tan ^2(x)\right ) \sqrt{\frac{a+b \tan ^4(x)}{\left (\sqrt{a}+\sqrt{b} \tan ^2(x)\right )^2}} F\left (2 \tan ^{-1}\left (\frac{\sqrt [4]{b} \tan (x)}{\sqrt [4]{a}}\right )|\frac{1}{2}\right )}{2 \sqrt [4]{a} \sqrt{a+b \tan ^4(x)}}+\frac{\sqrt [4]{a} \sqrt [4]{b} \left (\sqrt{a}+\sqrt{b} \tan ^2(x)\right ) \sqrt{\frac{a+b \tan ^4(x)}{\left (\sqrt{a}+\sqrt{b} \tan ^2(x)\right )^2}} E\left (2 \tan ^{-1}\left (\frac{\sqrt [4]{b} \tan (x)}{\sqrt [4]{a}}\right )|\frac{1}{2}\right )}{\sqrt{a+b \tan ^4(x)}}-\frac{\left (\sqrt{a}+\sqrt{b}\right ) (a+b) \left (\sqrt{a}+\sqrt{b} \tan ^2(x)\right ) \sqrt{\frac{a+b \tan ^4(x)}{\left (\sqrt{a}+\sqrt{b} \tan ^2(x)\right )^2}} \Pi \left (-\frac{\left (\sqrt{a}-\sqrt{b}\right )^2}{4 \sqrt{a} \sqrt{b}};2 \tan ^{-1}\left (\frac{\sqrt [4]{b} \tan (x)}{\sqrt [4]{a}}\right )|\frac{1}{2}\right )}{4 \sqrt [4]{a} \sqrt [4]{b} \left (\sqrt{a}-\sqrt{b}\right ) \sqrt{a+b \tan ^4(x)}} \]
Antiderivative was successfully verified.
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Rule 3670
Rule 1336
Rule 195
Rule 220
Rule 1209
Rule 1198
Rule 1196
Rule 1217
Rule 1707
Rubi steps
\begin{align*} \int \tan ^2(x) \sqrt{a+b \tan ^4(x)} \, dx &=\operatorname{Subst}\left (\int \frac{x^2 \sqrt{a+b x^4}}{1+x^2} \, dx,x,\tan (x)\right )\\ &=\operatorname{Subst}\left (\int \left (\sqrt{a+b x^4}-\frac{\sqrt{a+b x^4}}{1+x^2}\right ) \, dx,x,\tan (x)\right )\\ &=\operatorname{Subst}\left (\int \sqrt{a+b x^4} \, dx,x,\tan (x)\right )-\operatorname{Subst}\left (\int \frac{\sqrt{a+b x^4}}{1+x^2} \, dx,x,\tan (x)\right )\\ &=\frac{1}{3} \tan (x) \sqrt{a+b \tan ^4(x)}+\frac{1}{3} (2 a) \operatorname{Subst}\left (\int \frac{1}{\sqrt{a+b x^4}} \, dx,x,\tan (x)\right )-(a+b) \operatorname{Subst}\left (\int \frac{1}{\left (1+x^2\right ) \sqrt{a+b x^4}} \, dx,x,\tan (x)\right )+\operatorname{Subst}\left (\int \frac{b-b x^2}{\sqrt{a+b x^4}} \, dx,x,\tan (x)\right )\\ &=\frac{1}{3} \tan (x) \sqrt{a+b \tan ^4(x)}+\frac{a^{3/4} F\left (2 \tan ^{-1}\left (\frac{\sqrt [4]{b} \tan (x)}{\sqrt [4]{a}}\right )|\frac{1}{2}\right ) \left (\sqrt{a}+\sqrt{b} \tan ^2(x)\right ) \sqrt{\frac{a+b \tan ^4(x)}{\left (\sqrt{a}+\sqrt{b} \tan ^2(x)\right )^2}}}{3 \sqrt [4]{b} \sqrt{a+b \tan ^4(x)}}+\left (\sqrt{a} \sqrt{b}\right ) \operatorname{Subst}\left (\int \frac{1-\frac{\sqrt{b} x^2}{\sqrt{a}}}{\sqrt{a+b x^4}} \, dx,x,\tan (x)\right )-\left (\left (\sqrt{a}-\sqrt{b}\right ) \sqrt{b}\right ) \operatorname{Subst}\left (\int \frac{1}{\sqrt{a+b x^4}} \, dx,x,\tan (x)\right )-\frac{\left (\sqrt{a} (a+b)\right ) \operatorname{Subst}\left (\int \frac{1+\frac{\sqrt{b} x^2}{\sqrt{a}}}{\left (1+x^2\right ) \sqrt{a+b x^4}} \, dx,x,\tan (x)\right )}{\sqrt{a}-\sqrt{b}}+\frac{\left (\sqrt{b} (a+b)\right ) \operatorname{Subst}\left (\int \frac{1}{\sqrt{a+b x^4}} \, dx,x,\tan (x)\right )}{\sqrt{a}-\sqrt{b}}\\ &=-\frac{1}{2} \sqrt{a+b} \tan ^{-1}\left (\frac{\sqrt{a+b} \tan (x)}{\sqrt{a+b \tan ^4(x)}}\right )+\frac{1}{3} \tan (x) \sqrt{a+b \tan ^4(x)}-\frac{\sqrt{b} \tan (x) \sqrt{a+b \tan ^4(x)}}{\sqrt{a}+\sqrt{b} \tan ^2(x)}+\frac{\sqrt [4]{a} \sqrt [4]{b} E\left (2 \tan ^{-1}\left (\frac{\sqrt [4]{b} \tan (x)}{\sqrt [4]{a}}\right )|\frac{1}{2}\right ) \left (\sqrt{a}+\sqrt{b} \tan ^2(x)\right ) \sqrt{\frac{a+b \tan ^4(x)}{\left (\sqrt{a}+\sqrt{b} \tan ^2(x)\right )^2}}}{\sqrt{a+b \tan ^4(x)}}+\frac{a^{3/4} F\left (2 \tan ^{-1}\left (\frac{\sqrt [4]{b} \tan (x)}{\sqrt [4]{a}}\right )|\frac{1}{2}\right ) \left (\sqrt{a}+\sqrt{b} \tan ^2(x)\right ) \sqrt{\frac{a+b \tan ^4(x)}{\left (\sqrt{a}+\sqrt{b} \tan ^2(x)\right )^2}}}{3 \sqrt [4]{b} \sqrt{a+b \tan ^4(x)}}-\frac{\left (\sqrt{a}-\sqrt{b}\right ) \sqrt [4]{b} F\left (2 \tan ^{-1}\left (\frac{\sqrt [4]{b} \tan (x)}{\sqrt [4]{a}}\right )|\frac{1}{2}\right ) \left (\sqrt{a}+\sqrt{b} \tan ^2(x)\right ) \sqrt{\frac{a+b \tan ^4(x)}{\left (\sqrt{a}+\sqrt{b} \tan ^2(x)\right )^2}}}{2 \sqrt [4]{a} \sqrt{a+b \tan ^4(x)}}+\frac{\sqrt [4]{b} (a+b) F\left (2 \tan ^{-1}\left (\frac{\sqrt [4]{b} \tan (x)}{\sqrt [4]{a}}\right )|\frac{1}{2}\right ) \left (\sqrt{a}+\sqrt{b} \tan ^2(x)\right ) \sqrt{\frac{a+b \tan ^4(x)}{\left (\sqrt{a}+\sqrt{b} \tan ^2(x)\right )^2}}}{2 \sqrt [4]{a} \left (\sqrt{a}-\sqrt{b}\right ) \sqrt{a+b \tan ^4(x)}}-\frac{\left (\sqrt{a}+\sqrt{b}\right ) (a+b) \Pi \left (-\frac{\left (\sqrt{a}-\sqrt{b}\right )^2}{4 \sqrt{a} \sqrt{b}};2 \tan ^{-1}\left (\frac{\sqrt [4]{b} \tan (x)}{\sqrt [4]{a}}\right )|\frac{1}{2}\right ) \left (\sqrt{a}+\sqrt{b} \tan ^2(x)\right ) \sqrt{\frac{a+b \tan ^4(x)}{\left (\sqrt{a}+\sqrt{b} \tan ^2(x)\right )^2}}}{4 \sqrt [4]{a} \left (\sqrt{a}-\sqrt{b}\right ) \sqrt [4]{b} \sqrt{a+b \tan ^4(x)}}\\ \end{align*}
Mathematica [C] time = 16.8358, size = 550, normalized size = 0.86 \[ \left (\frac{\tan (x)}{3}-\frac{1}{2} \sin (2 x)\right ) \sqrt{\frac{4 a \cos (2 x)+a \cos (4 x)+3 a-4 b \cos (2 x)+b \cos (4 x)+3 b}{4 \cos (2 x)+\cos (4 x)+3}}+\frac{\left (3 \sqrt{a} \sqrt{b}-2 i a-3 i b\right ) \left (\tan ^2(x)+1\right ) \sqrt{\frac{b \tan ^4(x)}{a}+1} \text{EllipticF}\left (i \sinh ^{-1}\left (\sqrt{\frac{i \sqrt{b}}{\sqrt{a}}} \tan (x)\right ),-1\right )+3 b \sqrt{\frac{i \sqrt{b}}{\sqrt{a}}} \tan ^5(x)+3 a \sqrt{\frac{i \sqrt{b}}{\sqrt{a}}} \tan (x)-3 \sqrt{a} \sqrt{b} \left (\tan ^2(x)+1\right ) \sqrt{\frac{b \tan ^4(x)}{a}+1} E\left (\left .i \sinh ^{-1}\left (\sqrt{\frac{i \sqrt{b}}{\sqrt{a}}} \tan (x)\right )\right |-1\right )+3 i a \tan ^2(x) \sqrt{\frac{b \tan ^4(x)}{a}+1} \Pi \left (-\frac{i \sqrt{a}}{\sqrt{b}};\left .i \sinh ^{-1}\left (\sqrt{\frac{i \sqrt{b}}{\sqrt{a}}} \tan (x)\right )\right |-1\right )+3 i b \tan ^2(x) \sqrt{\frac{b \tan ^4(x)}{a}+1} \Pi \left (-\frac{i \sqrt{a}}{\sqrt{b}};\left .i \sinh ^{-1}\left (\sqrt{\frac{i \sqrt{b}}{\sqrt{a}}} \tan (x)\right )\right |-1\right )+3 i a \sqrt{\frac{b \tan ^4(x)}{a}+1} \Pi \left (-\frac{i \sqrt{a}}{\sqrt{b}};\left .i \sinh ^{-1}\left (\sqrt{\frac{i \sqrt{b}}{\sqrt{a}}} \tan (x)\right )\right |-1\right )+3 i b \sqrt{\frac{b \tan ^4(x)}{a}+1} \Pi \left (-\frac{i \sqrt{a}}{\sqrt{b}};\left .i \sinh ^{-1}\left (\sqrt{\frac{i \sqrt{b}}{\sqrt{a}}} \tan (x)\right )\right |-1\right )}{3 \sqrt{\frac{i \sqrt{b}}{\sqrt{a}}} \left (\tan ^2(x)+1\right ) \sqrt{a+b \tan ^4(x)}} \]
Antiderivative was successfully verified.
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Maple [C] time = 0.056, size = 537, normalized size = 0.8 \begin{align*} \text{result too large to display} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Maxima [F] time = 0., size = 0, normalized size = 0. \begin{align*} \int \sqrt{b \tan \left (x\right )^{4} + a} \tan \left (x\right )^{2}\,{d x} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Fricas [F(-1)] time = 0., size = 0, normalized size = 0. \begin{align*} \text{Timed out} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Sympy [F] time = 0., size = 0, normalized size = 0. \begin{align*} \int \sqrt{a + b \tan ^{4}{\left (x \right )}} \tan ^{2}{\left (x \right )}\, dx \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Giac [F] time = 0., size = 0, normalized size = 0. \begin{align*} \int \sqrt{b \tan \left (x\right )^{4} + a} \tan \left (x\right )^{2}\,{d x} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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